Quote:
Originally Posted by MikeB
This is a bit different from the solution path I was taught. I'm used to solving for one variable in terms of the other in one equation and substituting into the other equation.
So a + 2b = 4 resolves to a = 42b
Then substituting this for a into the other equation:
2(42b) +b =5 yields b=1
And so forth, same results...
ETA: Oh yeah, "Bite me Heinz" you socalled superior member! Heh.

My brain is insisting that your approach is the standard algebraic way to go about it  but it involves moving things from one side of the equation to the other. It involves rearranging things. Linear algebra doesn't let you rearrange things  you manipulate the entire formula, and you work across formulas rather than within.
Traditional algebra is intraformula solving; Linear algebra is interformula solving